How to Find Y-Intercepts

Last reviewed October 15, 2026

The y-intercept is the point where a graph meets the y-axis. Every point on that axis has x = 0, so the method is always the same: put x = 0 into the equation and work out y. It is usually the easiest point on a graph to find — and the one that most often tells you what the numbers mean.

The rule

Set x = 0 and solve for y. If the answer is b, the y-intercept is the point (0, b). For a function y = f(x), it is simply f(0).

For y = x² − 5x + 6, putting x = 0 leaves y = 6, so the y-intercept is (0, 6). Notice that every term with an x in it vanished: only the constant survives. That is the shortcut for any polynomial, and it is why the y-intercept is often called the initial value or starting value.

Lines in any form

Slope-intercept form

In y = mx + b, b is the y-intercept, which is where the form gets its name. y = 3x − 4 crosses the y-axis at (0, −4); y = −½x + 7 at (0, 7). Read the sign along with the number: y = 3x − 4 has b = −4, not 4.

Standard form

For Ax + By = C, put x = 0: By = C, so the y-intercept is (0, C/B). For 3x − 4y = 12, that is −4y = 12, giving (0, −3). Doing the same with y = 0 gives the x-intercept, (4, 0), and the two points together are the fastest way to draw the line.

3x − 4y = 12 meets the y-axis at (0, −3) and the x-axis at (4, 0): cover up each variable in turn. Open this in the intercept calculator.

Point-slope form

y − 5 = 2(x − 3) hides b. Put x = 0: y − 5 = −6, so y = −1 and the intercept is (0, −1). Expanding to y = 2x − 1 shows the same thing.

Horizontal and vertical lines

The horizontal line y = 4 crosses the y-axis at (0, 4). The vertical line x = 3 runs parallel to the y-axis and never meets it, so it has no y-intercept; x = 0 is the y-axis itself.

From two points

Given two points on a line, find the slope, then use either point to find b. Through (2, 5) and (6, 13):

  1. Slope: m = (13 − 5)/(6 − 2) = 8/4 = 2.
  2. Put (2, 5) into y = 2x + b: 5 = 4 + b, so b = 1.
  3. The y-intercept is (0, 1). Check with the other point: 2·6 + 1 = 13.

A shortcut: b = y₁ − m·x₁. You are walking back along the line from the known point to x = 0, x₁ steps at a time, each step changing y by m.

From a table or a graph

A table that includes x = 0

Read it off: the y-value in the x = 0 row is the y-intercept.

A table that does not

If the x-values go up in equal steps and the y-values change by the same amount each time, the data is linear: work backwards to x = 0. In the table below, each step of 1 in x adds 3 to y, so going from x = 1 back to x = 0 subtracts 3 from 7.

x1234
y7101316

The y-intercept is (0, 4), and the line is y = 3x + 4. If the y-values are multiplied by the same number each step instead, the data is exponential, and you divide backwards rather than subtract. For real data that is only roughly linear, fit a line first; the linear regression guide shows how, and the intercept of the fitted line is the estimate.

A graph

Find where the curve crosses the vertical axis and read the value. A graph gives a good estimate but rarely an exact one, so if you have the equation, use it to confirm.

Polynomials and exponentials

y = 3·2ˣ meets the y-axis at (0, 3), the a in a·bˣ. It never reaches the x-axis, so it has a y-intercept and no x-intercept. Open this in the intercept calculator.

Why a function has at most one

A function gives exactly one output for each input. The y-axis is the set of points with x = 0, so a function can meet it at most once, at (0, f(0)) — this is the vertical line test applied to the y-axis itself.

Equations that are not functions are not bound by this. The circle x² + y² = 25 gives y² = 25 when x = 0, so it meets the y-axis twice, at (0, 5) and (0, −5). A sideways parabola such as x = y² − 4 meets it at (0, 2) and (0, −2).

The circle x² + y² = 25 is not a function, so it can and does meet the y-axis twice. Open this in the intercept calculator.

When there is no y-intercept

A graph has no y-intercept exactly when it has no point with x = 0. That happens in four ways:

(x² + x)/x is the line y = x + 1 with the point (0, 1) removed: the hole sits exactly on the y-axis, so there is no y-intercept. Open this in the intercept calculator.

What the y-intercept means

When x measures time, x = 0 is the start, and the y-intercept is the value at the start. That makes it the number in a word problem most often asked about:

Sometimes the intercept is meaningless. A regression of weight against height may give a negative y-intercept: the weight of someone 0 inches tall. The line fits the data where the data is and says nothing about x = 0.

Mistakes that cost marks

  1. Setting y = 0 instead of x = 0. That finds the x-intercepts; see how to find x-intercepts.
  2. Dropping the sign of b. y = 2x − 5 crosses at (0, −5).
  3. Reading b from a line not in y = mx + b form. In 2x + 3y = 6, the 6 is not the y-intercept; (0, 2) is.
  4. Writing a number when a point is asked for: (0, 4), not 4.
  5. Simplifying first and reporting a y-intercept where the original function has a hole.
  6. Confusing the vertex with the y-intercept of a parabola.

Questions

How do you find the y-intercept of an equation?

Set x = 0 and solve for y. The result b gives the y-intercept at the point (0, b). For y = 3x − 4 that is (0, −4); for 2x + 5y = 10 it is 5y = 10, so (0, 2).

Is the y-intercept the same as b?

In slope-intercept form, y = mx + b, yes: b is the y-value where the line crosses the y-axis, so the y-intercept is (0, b). In other forms it is not written down directly, and you find it by putting x = 0.

Can a function have two y-intercepts?

No. A function gives exactly one output for each input, so at x = 0 it has at most one value, and its graph meets the y-axis at most once. An equation that is not a function can have more: the circle x² + y² = 25 meets the y-axis at (0, 5) and (0, −5).

Can a graph have no y-intercept?

Yes, whenever x = 0 is not in its domain. y = 1/x has a vertical asymptote on the y-axis, y = ln x and y = √(x − 2) are not defined at 0, and the vertical line x = 3 runs parallel to the y-axis. A rational function with a hole at x = 0 has none either.

How do you find the y-intercept from two points?

Work out the slope m = (y₂ − y₁)/(x₂ − x₁), then put one of the points into y = mx + b and solve for b. Through (2, 5) and (6, 13), m = 2, and 5 = 2·2 + b gives b = 1, so the y-intercept is (0, 1).

Find the intercepts of any function or equation